1. The NACRA 20 Minimum Sailing Weight shall be 325lbs; however, for crews requiring more than 25lbs. plus 1/2 of the additional weight required need be carried.

It says plus 1/2 of the additional weight required need to be carried. So the weight over the 25lbs needed to get to 325 only half needs to be carried. It does not say weight over the 25lbs needed plus the weight needed to get to 325 plus 1/2 that weight. The team is already at a disadvantage with not being able to move the weight when sailing and adding too much weight will make it hard to right the boat. Just my opinion.

I read that AS for the teams that have to carry more than 25lbs to make weight they have to carry minimum plus 1/2 of the difference.
What a horrible disadvantage when you get to sail at or below minimum while the heavy guys are WAY over. Gimme a break.

Kris, even worse we were at 480#s with a torn spinny.

You should see what else I told him to shave, or maybe not:) I also prescribed 20 oz prune juice with 3 oz rum for breakfast. It didn't help.

If that is the case, then I want the weight to be moveable, inboard, outboard, fore and aft, have legs and arms inwhich to trim, not be all hairy, perhaps even smell nice...

I'm getting some of the same interperitation here and I have to ask Really? Put yourself in my situation. You want 60#s additional weight, fixed, on the boat, with potentially all of it working against the masts floation while on its side. Really?

I have also done some short course racing with my son, so we were at the 285#s, without corrector weigths and the other teams with two humans on board just walked away from us since the wind was slightly stronger than what the two of us could hold down. At 10 years old he can trim the jib sometimes, he can trap out sometimes, he can call opposing boats, and he can always give me a rash of crap for making a decision that cost us a place or two. It not all Roses.

Looks like I should just take the single handed correction factor, good enough.

What did the factory/class say? I don't think the rules were written to make it a family boat ,they were written to keep light teams from taking advantage. The skill of the sailors aboard has no bearing on the handicap. I'd say talk to your fellow club members and come up with an equitable solution, it's not like your traveling and racing lots of different folks with your son.

Awaiting answer from the "Class"... Btw, I think the ideal weight is 350-365. Handles most conditions reasonable well, above those numbers and you are making compromises in certain condition and below those number making compromises in other conditions.

Hey, see you soon? Septembers just around the corner. Jerry asked about you when he called the other day asking about the Oxford race. Retirement is really good for him; I use to have to nag him to get him to come do Oxford, now he is calling four months in advance.

Right on. Maybe I can actually "Check in properly" this year, but I doubt it. Think they'd be pissed if I mooned them at check-in?

Ahhhh YEAH! Espcially since Jerry would be the next one to follow suit...

And yet you still beat me at 400#s and a non-torn spinny...

Here's my suggestion for how to affix the weight - go to West Marine and buy an anchor of the approximate weight needed. Get a line, tie one end to the anchor, the other to the crossbeam near the dolphin striker, then the toss the anchor into the water. It doesn't need to touch bottom.

Past two Tuesday nights been saling with board up 6 inches, sometimes downwind forget to pull them higher.

Thanks for the suggestion. Were you trying it out for me?

Orphan et all,

Stolen from F18 rules:
C.3 CREW
C.3.1 MEMBERSHIP
a) Crews are not permitted to enter a Formula 18 event unless they are current members of their NCA.
b) In countries where there is no NCA, the crew shall be member of the IF18CA.
C.3.2 LIMITATIONS
(a) The crew shall consist of 2 persons.
(b) The crew shall use the sails (as defined in G.2.3) in accordance with the following weight categories:
(1) Crew between 115 kg and 130 kg shall sail with the small jib and small spinnaker and then shall carry extra weight equal to half the difference between their actual weight and 130 kg.
(2) Crew between 130 kg and 140 kg shall sail with the small jib and the small spinnaker and shall not carry extra weight.
(3) Crew in between 140 kg and 150 kg may use the large jib and the large spinnaker and then shall carry extra weight equal to half the difference between their actual weight and 150 kg. International Formula 18 Class Rules 2010 9
(4) Crew weighing 150 kg and over may use the large jib and the large spinnaker without carrying any extra weight.
C.3.3 WEIGHTS
(a) The minimum combined crew weight is 115 kg
(b) They are four categories of crew weight:
(1) from 115 kg to less than 130 kg
(2) from 130 kg to 140 kg
(3) from 140 kg to 150 kg
(4) above 150 kg
(c) Crew corrector weights shall be of metal and securely fastened on the port side, either to the outside of the front crossbeam or to the strut, , and shall be removable for checking.

I was. It worked well.

Taken from an email from Trey:

"Chris, the scenario you present in Option 1 is the correct interpretation. After checking the original intent with the factory/board, it is agreed that in your case at 285lbs, you'll need 32.5lbs of additional weight onboard secured in the denoted location(s). If you or anyone else have any questions/concerns, please call me.

Trey Brown
N20 Class Director
N20 1017"

These were the options presented:

Option #1: Two crew weighting 285#, Required minimum of 325#, difference is 40#. Only the first 25# being required with only half of the remaining 15# being required resulting in a corrected crew weight total of 317.5#.

The math: 40#s - 25#s = 15#s * 0.5 =7.5#s + 25#s = 32.5#s

Corrector weight needed: 32.5#


Option #2: Since 40# is required then only half of the additional required weight is needed resulting in a corrected crew weight total of 305#.

The math: 40#s * 0.5 = 20#s

Corrector weight needed: 20#


Option #3: Since 40# is required then an additional half of the 40#s is needed resulting in a corrected crew weight total of 345#.

The math: 40#s + 40#s * 0.5 = 60#s

Corrector weight needed: 60#


Option #4: Since 40# is required then the first 40# is needed with an additional half of the 15#s being also required resulting in a corrected crew weight total of 332.5#.

The math: 40 + (15 * 0.5) = 47.5#

Corrector weight needed: 47.5#

Trey can do math?